We ned to have to solve the problem regarding Julian dates...
Like this string, 070360 which is = dec 26 2007 something...
Anybody please post a code solution for this issue.
This is another breakthrough for all of you guys. Any help will be greatly appreciated.
cal_from_jd
(PHP 4 >= 4.1.0, PHP 5)
cal_from_jd — Converte à partir do "Julian Day Count" para um outro calendário suportado
Descrição
array cal_from_jd
( int $jd
, int $calendário
)
cal_from_jd() converte do "Julian Day Count" ( jd) para uma data de um calendário especificado. Os valores dos calendários suportados são CAL_GREGORIAN, CAL_JULIAN, CAL_JEWISH e CAL_FRENCH.
Exemplo #1 cal_from_jd() exemplo
<?php
$hoje = unixtojd(mktime(0, 0, 0, 8, 16, 2003));
print_r(cal_from_jd($hoje, CAL_GREGORIAN));
?>
Este código retorna:
Array
(
[date] => 8/16/2003
[month] => 8
[day] => 16
[year] => 2003
[dow] => 6
[abbrevdayname] => Sat
[dayname] => Saturday
[abbrevmonth] => Aug
[monthname] => August
)
Veja também cal_to_jd().
User Contributed Notes
cal_from_jd
cal_from_jd
edwardo duarte at yahuu dat kom
05-Dec-2007 04:13
05-Dec-2007 04:13

cal_days_in_month