localeconv
Guys, if += 0 is producing wrong values sometimes, and preg_replace is cpu consuming, then just stick to the main function described on that page, and use:
<?php
$value = ltrim($value, '0');
?>
should be the fastest and most reliable.
I think all those comments can be misleading for begginers checking this page - it's sort of using magic tricks to reinvent the wheel.
ltrim
(PHP 4, PHP 5)
ltrim — Retira espaços em branco (ou outros caracteres) do início da string
Descrição
string ltrim
( string $str
[, string $charlist
] )
Retira espaços em branco (ou outros caracteres) do início de uma string.
Parâmetros
- str
-
A string de entrada.
- charlist
-
Você pode também especificar os caracteres que você quer retirar, para isso, use o parâmetro charlist. Simplesmente liste todos os caracteres que você quer que seja removido. Com .. você pode especificar um intervalo de caracteres.
Valor Retornado
Esta função retorna uma string com whitespace retirados do início de str. Sem o segundo parâmetro, ltrim() retirará estes caracteres:
- " " (ASCII 32 (0x20)), um espaço normal.
- "\t" (ASCII 9 (0x09)), uma tabulação.
- "\n" (ASCII 10 (0x0A)), uma linha nova (line feed).
- "\r" (ASCII 13 (0x0D)), um retono de carro.
- "\0" (ASCII 0 (0x00)), o byte NULL.
- "\x0B" (ASCII 11 (0x0B)), uma tabulação vertical.
Histórico
| Versão | Descrição |
|---|---|
| 4.1.0 | O parâmetro charlist foi adicionado. |
Exemplos
Exemplo #1 Exemplo de uso da ltrim()
<?php
$text = "\t\tThese are a few words :) ... ";
$binary = "\x09Example string\x0A";
$hello = "Hello World";
var_dump($text, $binary, $hello);
print "\n";
$trimmed = ltrim($text);
var_dump($trimmed);
$trimmed = ltrim($text, " \t.");
var_dump($trimmed);
$trimmed = ltrim($hello, "Hdle");
var_dump($trimmed);
// trim the ASCII control characters at the beginning of $binary
// (from 0 to 31 inclusive)
$clean = ltrim($binary, "\x00..\x1F");
var_dump($clean);
?>
O exemplo acima irá imprimir:
string(32) " These are a few words :) ... " string(16) " Example string " string(11) "Hello World" string(30) "These are a few words :) ... " string(30) "These are a few words :) ... " string(7) "o World" string(15) "Example string "
User Contributed Notes
ltrim
ltrim
dzek dot remove_this at dzek dot eu
24-Jul-2011 10:27
24-Jul-2011 10:27
Mike
08-Jan-2011 10:03
08-Jan-2011 10:03
Keep in mind the amount of resources preg_replace() uses.
I would suggest a simple if statement if you need to parse through large amounts of data.
<?php
function remove_leading_zeros_from_number($number_string) {
$limit = 9000.1
$temp = $number
(float) $temp;
if ($number < $limit) {
$number += 0;
} else {
preg_replace('~^[0]*([1-9][0-9]*)$~','$1',$number_string)
}
}
?>
Code is untested, but probably sound.
tanmar.de
06-May-2010 07:36
06-May-2010 07:36
The neat trick from Mr. Sherwood has only one ugly side-effect: If the "number" contained in the string is considerably large, you will end up with an int (or float) value that has nothing to do with the original number ...
You may use preg_replace instead:
$number_string = preg_replace('~^[0]*([1-9][0-9]*)$~','$1',$number_string);
This kills any leading zeros safely without changing any other data.
Hope this helps.
Usamah M dot Ali (usamah1228 at gmail dot com)
04-Feb-2008 12:42
04-Feb-2008 12:42
For those who use right-to-left languages such as Arabic, Hebrew, etc., it's worth mentioning that ltrim() (which stands for left trim) & rtrim() (which stands for right trim) DO NOT work contextually. The nomenclature is rather semantically incorrect. So in an RTL script, ltrim() will trim text from the right direction (i.e. beginning of RTL strings), and rtrim() will trim text from the left direction (i.e. end of RTL strings).
John Sherwood
06-Aug-2006 09:13
06-Aug-2006 09:13
To remove leading/trailing zeroes (example: "0123.4560"), doing a += 0 is easier than trim tricks.